Question

object is placed in front of a diverging lens with a focal length of 6 CM. Find the image distance for an object distance of 9 cm. Answer in units of cm.

Answer 1

Solution:-

given

u = - 9 cm

f = -6 cm

lens formula

$\frac{1}{v} - \frac{1}{u}=\frac{1}{f}$

$\frac{1}{v} =\frac{1}{u}+\frac{1}{f}$

Putting values

$\frac{1}{v} =\frac{1}{-9}+\frac{1}{-6}$

$\frac{1}{v} =\frac{-2-3}{18}$

$\boxed{V = {-18\over 5}cm}$ i.e image distance