Answer to Question #181575 in Optics for anuj

Question #181575

object is placed in front of a diverging lens with a focal length of 6 CM. Find the image distance for an object distance of 9 cm. Answer in units of cm.


1
Expert's answer
2021-04-19T17:11:45-0400

Solution:-


given

u = - 9 cm

f = -6 cm

lens formula


1v1u=1f\frac{1}{v} - \frac{1}{u}=\frac{1}{f}


1v=1u+1f\frac{1}{v} =\frac{1}{u}+\frac{1}{f}


Putting values


1v=19+16\frac{1}{v} =\frac{1}{-9}+\frac{1}{-6}



1v=2318\frac{1}{v} =\frac{-2-3}{18}



V=185cm\boxed{V = {-18\over 5}cm} i.e image distance




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