Answer to Question #177193 in Optics for Sujin

Question #177193

Calculate the optical invariant for a photographic objective with F = 50 mm. N = 2, field of view +26.6°.


1
Expert's answer
2021-04-06T06:24:50-0400

Given,

"F=50mm=50\\times 10^{-3}m"

"N=2"

View angle "(\\theta) =\\pm 26.6^\\circ"

Optical invariant "(I)=FN\\sin\\theta"

Now, substituting the values,

"(I)=50\\times 10^{-3}\\times 2\\times \\sin(26.6^\\circ)"

"\\Rightarrow (I)=0.1\\times \\sin(26.6^\\circ)"

"=0.1\\times 0.447"

"=0.0447"

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