What power of spectacle lens is needed to correct the vision of a nearsighted person whose far point is 30.0cm. Assume the spectacle lens is held 1.50cm away from the eye by eyeglass frames.
Given,
Far point of the person = 30cm
Distance between eye and eyeglass frame =1.5 cm
So, image distance
Here the distance is negative because it is in same side of the spectacle as the object.
Object distance
We know that,
Now, substituting the values,
We know that,
Power of lens
Here, negative sign representing that the lens should be concave.
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