Question #164234

Deduce expressions for the frequency heard by an observer

(a.) when he is stationary and a source of sound is moving towards him and

(b.) when he is moving towards a stationary source of sound.

      Explain your reasoning carefully in each case.



1
Expert's answer
2021-03-10T17:22:33-0500

Answer

a) according to concepts and theory

frequency of observer

f0=vλeff=vvTvsTf_0=\frac{v}{\lambda_{eff}}\\=\frac{v}{vT-v_sT}

s indicates for source and 0 for observer.

T=1fs\frac{1}{f_s}

when he is stationary and a source of sound is moving towards him then

f0=vvvsfsf_0=\frac{v}{v-v_s}f_s


b) similiarly

when he is moving towards a stationary source of sound

Then frequency of observer

Is given as

f0=v+vsv1T=v+vsvfsf_0=\frac{v+v_s}{v}\frac{1}{T}\\=\frac{v+v_s}{v}f_s



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