A source of sound frequency 550Hz emits waves of wavelength 600 mm in air at 20°C. What is the
velocity of sound in air at this temperature? What will be the wavelength of the sound from this source in air at 0°C?
Given quantities:
λ=600mm=0.6m frequency f=550Hz\lambda = 600mm =0.6m \space\space\space\space frequency \space\space f = 550Hzλ=600mm=0.6m frequency f=550Hz
velocity of sound v=fλ=0.6∗550=330m/sv = f\lambda = 0.6*550 = 330 m/sv=fλ=0.6∗550=330m/s
We know, v∽Tv \backsim \sqrt{T}v∽T
here, T1=t1+273=20+273=293KT_1 = t_1 + 273 = 20+273 = 293KT1=t1+273=20+273=293K
T2=t2+272=0+273=273KT_2 = t_2 + 272 = 0+273 = 273KT2=t2+272=0+273=273K
→vv1v2=T1T2→v2=v1∗T2T1=\to \large\frac{vv_1}{v_2} = \sqrt{\frac{T_1}{T_2}} \to v_2 = v_1*\sqrt{\frac{T_2}{T_1}} =→v2vv1=T2T1→v2=v1∗T1T2= 330∗273293=330*\large\frac{273}{293} =330∗293273= 318.5m/s318.5m/s318.5m/s
λ2=v2f=318.5550\lambda_2 = \large\frac{v_2}{f} = \frac{318.5}{550}λ2=fv2=550318.5 =0.579m→579mm= 0.579m\to 579mm=0.579m→579mm
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