A 2.00m long wire having a mass of 0.100kg is fixed at both ends. The tension in the wire is maintained at 20.0N
Remember that the harmonics of a vibrating string have frequencies that are related by integer multiples of the fundamental frequency of standing wave. For second part first we find numbers of waves present in the string and finally using that wave length we find frequency of string.
From the data we can find the linear density of wire and it is used to find the fundamental frequency and next three allowed modes.
Given,
Length of wire
Mass of wire
Liner density of the wire is
Tension in the wire
(a)Fundamental frequency of the wire is
The frequencies of the remaining normal modes are integral multiples of the fundamental frequency.
Therefore the frequency of the second allowed mode of vibration is
10Hz
The frequency of the third allowed mode of vibration is
15 Hz
(b)The distance between the two nodes is
So the wavelength is
Number of waves in the length is
waves
Numbers of modes present in the waves are
Frequency of the wave is
= 25 Hz
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