Question

A ray of light is incident at 60degrees in air on air-glass plane surface. Find the angle of refraction in the glass (n for glass = 1.5)

Answer 1

Let's write the Snell's Law:

$$n_isin\theta_i=n_rsin\theta_r,$$ $$\theta_r=sin^{-1}(\dfrac{n_isin\theta_i}{n_r}),$$ $$\theta_r=sin^{-1}(\dfrac{1.0\cdot sin60^{\circ}}{1.5})=35.3^{\circ}.$$