Answer to Question #162593 in Optics for Hillary

Question #162593

A ray of light is incident at 60degrees in air on air-glass plane surface. Find the angle of refraction in the glass (n for glass = 1.5)


1
Expert's answer
2021-03-08T08:33:19-0500

Let's write the Snell's Law:


nisinθi=nrsinθr,n_isin\theta_i=n_rsin\theta_r,θr=sin1(nisinθinr),\theta_r=sin^{-1}(\dfrac{n_isin\theta_i}{n_r}),θr=sin1(1.0sin601.5)=35.3.\theta_r=sin^{-1}(\dfrac{1.0\cdot sin60^{\circ}}{1.5})=35.3^{\circ}.

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