Answer to Question #154832 in Optics for Yershad

Question

Consider a wavelength multiplexer made from

circulators and fiber Bragg gratings. Assume the

input optical power of each wavelength is through

24 is 1 mW. Let both the insertion loss and the

throughput loss of each FBG be 0.25 dB, and let the

insertion loss of a circulator be 0.6 dB. What is the

power level of each wavelength in through h4

emerging from the final circulator ?

Answer 1

$P_m=(P_o)4+10\log \left(\frac{W}{T}\right)$

$P_o=\log 24$

$P_o=1.380$

$P_m=(1.380)4+10\log \left(\frac{0.25}{0.6}\right)=1.718mW$