Question #154832



Consider a wavelength multiplexer made from


circulators and fiber Bragg gratings. Assume the


input optical power of each wavelength is through


24 is 1 mW. Let both the insertion loss and the


throughput loss of each FBG be 0.25 dB, and let the


insertion loss of a circulator be 0.6 dB. What is the


power level of each wavelength in through h4


emerging from the final circulator ?


1
Expert's answer
2021-01-13T11:44:14-0500

Pm=(Po)4+10log(WT)P_m=(P_o)4+10\log \left(\frac{W}{T}\right)

Po=log24P_o=\log 24

Po=1.380P_o=1.380

Pm=(1.380)4+10log(0.250.6)=1.718mWP_m=(1.380)4+10\log \left(\frac{0.25}{0.6}\right)=1.718mW



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