A parallel polarized wave is incident from air into paraffin having relative permittivity 3, the value of its Brewster angle is
Answer
Brewster angle is given by
θ=tan−1(ϵr′ϵr)\theta=\tan^{-1} (\sqrt{\frac{\epsilon_{r'}}{ \epsilon_{r} }})θ=tan−1(ϵrϵr′)
=tan−1(31)=60°=\tan^{-1} (\sqrt{\frac{3}{1}}) =60^°=tan−1(13)=60°
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