Question

what is the power of prism in prism diopter that deviates a light ray of 6 cm at a distance of 500cm

Answer 1

$Power$ $of$ $prism$ $( \Delta$ $)$ $=$ $Distance$ $beyond$ $the$ $prism(cm)$ $/deviation$ $distance(cm)$

$\Delta$ $=500cm/6cm$

$\Delta$ $=83.33\Delta$