Question

a light beam strikes the surface of glass at a 60° angle to the normal.determine the angle of refraction . given the refracted index of glass and air is 1.5 and 1.0.

Answer 1

a light beam strikes the surface of glass at a 60° angle to the normal

$\theta_1$ = 60^o and $\theta_2$ - angle of refraction

we use Snell's law for determine angle of refraction - $\frac{sin\theta_1 }{sin\theta_2} = \frac{\nu_1}{\nu_2} = \frac{n_2}{n_2}$

here n - refraction index

n₁ = 1.0 for air and n₂ = 1.5 for glass

$\frac{sin60^o}{sin\theta_2} = \frac{\frac{3}{2}}{1}$ -> $sin\theta_2= \frac{2sin60^o}{3} = \frac{1}{\sqrt{3}}$ -> $\theta_2 = 35.3^o$