Question #146741
Consider 575 nm wavelength yellow light falling on a diffraction grating having 1500 lines per centimeter.

Randomized Variables
λ = 575 nm


Find the angle (in degrees) for the third-order maximum for the yellow light.
1
Expert's answer
2020-11-30T14:56:43-0500

The wavelength of yellow light λ = 575 nm = 5.75 \times 10^{-7} \; m

The number of lines N = 1500 lines per cm

N=1.5×105N= 1.5 \times 10^5

The slit separation:

d=1Nd = \frac{1}{N}

d=6.67×106  md = 6.67 \times 10^{-6} \; m

Let the angle for third-order maximum be theta

d×sinθ=n×λd \times sinθ = n \times λ

For third maximum

6.67×106×sinθ=3×5.75×1076.67 \times 10^{-6} \times sinθ = 3 \times 5.75 \times 10^{-7}

sinθ = 0.2586

θ = 14.98 degree

The angle for the third-order maximum for the yellow light is 14.98 degree.


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