Question #144650
You can determine the index of refraction of a substance by measuring its critical angle for total internal reflection.

Randomized Variables
Θc,w = 74.6°

(a) What is the index of refraction of a substance that has a critical angle of 74.6° when submerged in water (with index of refraction 1.333)?
(b) What would the critical angle be for this substance in air?
1
Expert's answer
2020-11-20T07:13:17-0500

(a)

n1=?n_1 = ?

n2=1.333n_2 = 1.333

θc=74.6ºθ_c = 74.6º

n1=n2sin(θc)n_1 = \frac{n_2}{sin(θ_c)}

n1=1.333sin(74.6º)=1.3330.9641=1.3826n_1 = \frac{1.333}{sin(74.6º)} = \frac{1.333}{0.9641} = 1.3826

(b) θc=sin1n2n1θ_c = sin^{-1}\frac{n_2}{n_1}

θc=sin11.0002931.3826=sin1(0.72348)=46.34ºθ_c = sin^{-1}\frac{1.000293}{1.3826}= sin^{-1}(0.72348) = 46.34º


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