As per the given question,
Wavelength of the wave "(\\lambda)=550nm"
"\\theta=23^\\circ"
"\\sin \\theta =n\\frac{\\lambda}{d}"
from bright fringe n = 1
Now, substituting the values
"\\sin 23^\\circ =1\\times \\frac{550\\times 10^{-9}m}{d}"
"\\Rightarrow d = \\frac{5.5\\times 10^{-9}}{0.39}"
"\\Rightarrow d = 14.1\\times 10^{-9}m"
"d=0.0141\\mu m"
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