Question #142890

. Skew rays are accepted into a large core diameter compared to the wavelength of thetransmitted light) step index fiber in air at a maximum axial angle of 450. Within the fiberthey change direction by 900at each reflection. Determine the acceptance angle formeridional rays or the fiber in air

Expert's answer

Given,

Axial angle (θas)=45(\theta_{as}) =45^\circ

As per the question, skew changes the direction by 9090^\circ at each reflection,

hence, γ=45\gamma=45^\circ

θas=sin1(NAcosγ)\theta_{as}=\sin^{-1}(\frac{NA}{\cos\gamma})

NA=sin(θas)×cos(γ)\Rightarrow NA= \sin(\theta_{as})\times \cos(\gamma)

NA=sin(45)×cos(45)\Rightarrow NA = \sin(45)\times \cos(45^\circ)

NA=12\Rightarrow NA =\frac{1}{2}

Now, Acceptance angle for meridional rays θa=sin1(NA)\theta_{a}=\sin^{-1}(NA)

θa=sin1(0.5)\Rightarrow \theta_{a}=\sin^{-1}(0.5)

θa=30\Rightarrow \theta_{a}=30^\circ


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