1di+1do=1f\frac {1}{d_i}+\frac {1}{d_o}=\frac{1}{f}di1+do1=f1
Therefore, 1di=15.4−12\frac{1}{d_i}=\frac{1}{5.4}-\frac{1}{2}di1=5.41−21
di=−0.31d_i=-0.31di=−0.31
Magnification=dido=(−1)−0,3150.5Magnification= \frac{d_i}{d_o}= \frac {(-1)-0,315}{0.5}Magnification=dodi=0.5(−1)−0,315
M=0.63. Which means the image is virtual, upright, enlarged
Answer is d
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