Question

A 3.0cm y’all object is placed 22 cm in front of a converging lens a real image is formed 11 cm from the lens what is the size of the image

Answer 1

$d_o=22cm$

$d_i=11cm$

$Magnification=\frac{d_i}{d_o}=\frac{11}{22}$

$M=0.5$

$h_i=0.5\times3.0=1.5cm$

Therefore height of image = 1.5cm.