Question #135135
In a Newton’s ring arrangement, light consisting of wavelengths and incidents normally on a plane convex lens of radius of curvature R resting on a glass plate. If the nth dark ring due to coincides with (n+1)th dark ring due to , then show that the radius of the nth dark ring of is given by .
1
Expert's answer
2020-09-28T08:08:54-0400

solution

in Newton ring experiment

radius of nth dark fringe can be written as

rn=nλRμr_n=\sqrt{\frac {n\lambda R}{\mu}}

for air μ=1\mu=1


rn=nλRr_n=\sqrt{n\lambda R}

similarly for (n+1)th newton ring radius can be shown as


rn+1=(n+1)λRμr_{n+1}=\sqrt{\frac {(n+1)\lambda R}{\mu}}

for air μ=1\mu=1


rn+1=(n+1)λRr_{n+1}=\sqrt{(n+1)\lambda R}


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