Question #133760
Calculate the focusing power of the lens in the fish eye. Assume that the lens is spherical
with a diameter of 2 mm. The index of refraction for water is 1.33, the lens index of refraction 1.4,
and vitreous humor and aqueous humor have similar refrection index 1.34.
1
Expert's answer
2020-09-21T08:32:17-0400

D=2  mmD = 2 \;mm

R=D2=1  mm=0.1  cmR = \frac{D}{2} = 1 \;mm = 0.1 \;cm

Mlens=1.4M_{lens} = 1.4

Mah=1.34M_{ah} = 1.34

R1=+RR_1 = +R

R2=RR_2=-R

1f=(MlensMah1)(1R11R2)\frac{1}{f} = (\frac{M_{lens}}{M_{ah}} -1)(\frac{1}{R_1} – \frac{1}{R_2})

1f=(1.41.341)(2R)\frac{1}{f} = (\frac{1.4}{1.34} – 1)(\frac{2}{R})

P=1f=0.0447×20=0.894  DioptreP = \frac{1}{f} = 0.0447\times20=0.894 \;Dioptre

Answer: 0.894 Dioptre

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