D=2 mmD = 2 \;mmD=2mm
R=D2=1 mm=0.1 cmR = \frac{D}{2} = 1 \;mm = 0.1 \;cmR=2D=1mm=0.1cm
Mlens=1.4M_{lens} = 1.4Mlens=1.4
Mah=1.34M_{ah} = 1.34Mah=1.34
R1=+RR_1 = +RR1=+R
R2=−RR_2=-RR2=−R
1f=(MlensMah−1)(1R1–1R2)\frac{1}{f} = (\frac{M_{lens}}{M_{ah}} -1)(\frac{1}{R_1} – \frac{1}{R_2})f1=(MahMlens−1)(R11–R21)
1f=(1.41.34–1)(2R)\frac{1}{f} = (\frac{1.4}{1.34} – 1)(\frac{2}{R})f1=(1.341.4–1)(R2)
P=1f=0.0447×20=0.894 DioptreP = \frac{1}{f} = 0.0447\times20=0.894 \;DioptreP=f1=0.0447×20=0.894Dioptre
Answer: 0.894 Dioptre
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