For a dark fringe to be formed, dyD=λ\frac {dy}{D}=\lambdaDdy=λ
λ=600nm=600×10−9\lambda=600nm= 600\times 10^{-9}λ=600nm=600×10−9
d=1mm=10−3d= 1mm= 10^{-3}d=1mm=10−3
D=2mD=2mD=2m D=2m
y=Dyd=2×600×10−9)10−3=1.2mmy=\frac {Dy}{d}= \frac {2\times 600\times10^{-9})}{10^{-3}}= 1.2mmy=dDy=10−32×600×10−9)=1.2mm
The distance between the first dark fringe on either side of the central beam is
2×y=2×1.2=2.4mm.2\times y= 2\times1.2= 2.4mm.2×y=2×1.2=2.4mm.
Thus Answer is 2.4mm2.4mm2.4mm
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