For a dark fringe to be formed, "\\frac {dy}{D}=\\lambda"
"\\lambda=600nm= 600\\times 10^{-9}"
"d= 1mm= 10^{-3}"
"D=2m" D=2m
"y=\\frac {Dy}{d}= \\frac {2\\times 600\\times10^{-9})}{10^{-3}}= 1.2mm"
The distance between the first dark fringe on either side of the central beam is
"2\\times y= 2\\times1.2= 2.4mm."
Thus Answer is "2.4mm"
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