Question #131398
A beam of light of wavelength 600 nm from distant source for a single slit 1 mm wide and resulting diffraction pattern is observed on a screen 2cm away. The distance between the First dark fringe on either side of the central Maximum is
1
Expert's answer
2020-09-03T14:14:35-0400

For a dark fringe to be formed, dyD=λ\frac {dy}{D}=\lambda

λ=600nm=600×109\lambda=600nm= 600\times 10^{-9}


d=1mm=103d= 1mm= 10^{-3}


D=2mD=2m D=2m


y=Dyd=2×600×109)103=1.2mmy=\frac {Dy}{d}= \frac {2\times 600\times10^{-9})}{10^{-3}}= 1.2mm


The distance between the first dark fringe on either side of the central beam is


2×y=2×1.2=2.4mm.2\times y= 2\times1.2= 2.4mm.


Thus Answer is 2.4mm2.4mm


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