Question #131394

When a movable mirror of michelson interferometer is moved through a distance of 0.030 mm under illumination of wavelength 6000 angstrom, the number of displaced fringes is

Expert's answer

d=mλ2d=\frac {m\lambda}{2}. Therefore,


0.030=300m0.030=300m


0.030mm=m×600020.030mm=\frac{m\times6000}{2}


Thus: m=0.00001m=0.00001

The number of fringes is 0.00001


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