d=mλ2d=\frac {m\lambda}{2}d=2mλ. Therefore,
0.030=300m0.030=300m0.030=300m
0.030mm=m×600020.030mm=\frac{m\times6000}{2}0.030mm=2m×6000
Thus: m=0.00001m=0.00001m=0.00001
The number of fringes is 0.00001
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