Question

For normal incidence of light from a medium of refractive index 1.42 onto a medium of refractive index 1.64.calculate the refection and transmission coefficents.

Answer 1

solution:-

given data

refractive index of medium 1 $(n_1)$ =1.42

refractive index of medium 2$(n_2)=1.64$

the reflection coefficient can be written

$R=\frac{(n_2-n_1)^2}{(n_2+n_1)^2}$

$=\frac{(1.64-1.42)^2}{(1.64+1.42)^2}$

$=\frac{(0.22)^2}{(3.06)^2}$

$\fcolorbox{red}{yellow}{$R=0.0052$}$

therefore reflection coefficient is 0.0052

relation between reflection and transmission coefficient can be written as

$T+R=1$

$T=1-R$

by putting the value of R

$T=1-0.0052$

$\fcolorbox{red}{yellow}{$T=0.9948$}$

therefore transmission coefficient is 0.9948 .