Question

A 40hz vibration generate a wave in a ripple tank if the speed of the wave in two different length of the tank are 0.8m/s and 0.5m/s calculate the different between the lengrh.

Answer 1

$\lambda=\frac{v}{f}$ therefore, The first distance $\lambda$ ₁₌$.\frac{0.8m/s}{40hz}=0.02m$ The second distance $\lambda$ ₂₌$\frac{0.5m/s}{40}=0.013m$ . The difference is $\lambda$₁-$\lambda$ ₂ =0.02m-0.013m= .0007m≈ 0.01m.