Question

in case of practical of refraction what will be the angle of deviation if the angle of incidence is 10, 20, 30, 40, 50, 60, 70

Answer 1

The angle of deviation is $\delta=\theta-\rho.$

First, find the angle of refraction:

$$\rho(\theta)=\text{arcsin}\frac{\text{sin}\theta}{n}.$$

With refraction index $n=1.6$ we have the following data:

$\rho(10°)=6°,\space\delta(10°)=4°;\\ \rho(20°)=12°,\space\delta(20°)=8°;\\ \rho(30°)=18°,\space\delta(30°)=12°;\\ \rho(40°)=24°,\space\delta(40°)=16°;\\ \rho(50°)=29°,\space\delta(50°)=21°;\\ \rho(60°)=33°,\space\delta(60°)=27°;\\ \rho(70°)=36°,\space\delta(70°)=34°.\\$