Answer to Question #127637 in Optics for Aqib

Question

A plan wave(500A•) falls normally on a long narrow slit of width 0.5mn. Calculate the angles of diffraction corresponding to the first three minima. Repeat the calculations crossponding width of 0.1mm. Interpred physically the change in the diffraction pattern.

Answer 1

As per the question,

Wavelength of the plane wave $(\lambda)=500 A^\circ =500\times 10^{-10}m$

Width of the slit $=0.5 mm = 5\times 10^{-4}m$

Angle of diffraction = ?

$\theta =\frac{\lambda}{w}$

$\theta = \frac{500 \times 10^{-10}m}{5\times 10^{-4}m} =1\times 10^{-4} radian$

similarly,

$\theta' = \frac{500 \times 10^{-10}m}{1\times 10^{-4}m} =5\times 10^{-4} radian$