what is the nature and focal length of the lens that will form a virtual image having one-quarter the dimensions of an object spaced 40 cm from the lens?
1
Expert's answer
2020-07-27T09:35:31-0400
The formula for finding Focal length ia;
u1+v1=f1
v=40
u=10
101+401=f1
Reducing the sum you find 81
As a result the focal length is 8 cm while the nature of the lens is convex since the power is positive.
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