As per the question,
The wavelength of the light "(\\lambda)=460nm"
n =320 dark fringe
Let the thickness be e,
"e=\\frac{m\\lambda }{2}"
"\\Rightarrow e=\\frac{320\\times 460\\times 10^{-9}m}{2}"
"\\Rightarrow e=73.6\\times 10^{-6}m"
"\\Rightarrow e =73.6\\mu m"
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