Question

The angle of diffracted X-rays is 90 degree from the incident direction of X-rays. The interplanner seperation of the planes responsible for the diffraction is?

Answer 1

According to Bragg's law for n=1:

$$\lambda=2d\text{ sin}\theta.$$

Hence, the interplanar spacing is

$$d=\frac{\lambda}{2\text{sin}\theta}=\frac{\lambda}{2}.$$