"d=1\/6000=1.67\\cdot 10^{-6}m"
"d(\\sin\\theta_m+\\sin\\theta_i )=m\\lambda"
For "\\theta_m=90\u00b0"
"m=\\frac{d(\\sin\\theta_m+\\sin\\theta_i )}{\\lambda}=\\frac{1.67\\cdot10^{-6}(\\sin90\u00b0+\\sin30\u00b0 )}{5460\\cdot10^{-10}}=1.52\\approx2"
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