As per the question,
focal length of the glass=100/2.7cm=100/2.7 cm=100/2.7cm
let image position form the lens is v,
1v=1f+1u=2.7100−156\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}=\dfrac{2.7}{100}-\dfrac{1}{56}v1=f1+u1=1002.7−561
v=109.37cmv=109.37cmv=109.37cm
Now, u=fvv−f=62.5.0×109.37109.37−62.5=145.84cmu=\dfrac{fv}{v-f}=\dfrac{62.5.0\times 109.37}{109.37-62.5}=145.84cmu=v−ffv=109.37−62.562.5.0×109.37=145.84cm
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