Answer to Question #117320 in Optics for shreevathsa BK

Question #117320
With a laser, fringes remain clearly visible, when the path difference was increased up to X m, Deduce Coherence time and spectral half width given λ = 11.5x10-7 m.
X = 1.768 T = 77323
1
Expert's answer
2020-05-21T13:11:09-0400

As per the question,

Wavelength of the laser beam (λ)=11.5×107m(\lambda)=11.5\times 10^{-7}m

Speed of light (c)=3×108m/sec(c)=3\times 10^8 m/sec

lcoh=1.768ml_{coh}=1.768m

tcoh=lcohc=1.7683×108sec=5.9×109=5.9nst_{coh}=\dfrac{l_{coh}}{c}=\dfrac{1.768}{3\times 10^{8}}sec=5.9\times 10^{-9}=5.9ns


Δλ=λ2l=(11.5×107)21.768=74.8×1014m=7.48×1015m\Delta \lambda=\dfrac{\lambda^2}{l}=\dfrac{(11.5\times 10^{-7})^2}{1.768}=74.8\times 10^{-14}m=7.48\times 10^{-15}m


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