Question #112838
the magnifying glass is made of lenses of power +20D and -4D. if distance of distinct vision is 25cm. calculate the size of an object 2cm high seen through the magnifying glass
1
Expert's answer
2020-04-29T09:48:31-0400

As per the given question,

The power of the lenses are (P1)=+20D(P_1)=+20D and (P2)=4D(P_2)=-4D

distance of distinct vision (v) =25cm

The size of the object (ho)=2cm(h_o)=2cm

Let the focal length of the glasses are f1f_1 and f2f_2

We know that,

f1=1P1=10020=5cmf_1=\dfrac{1}{P_1}=\dfrac{100}{20}=5cm

Similarly,

f2=1P2=1004=25cmf_2=\dfrac{1}{P_2}=\dfrac{-100}{4}=-25cm

Now, combined focal length 1f=1f1+1f2=15125=425\dfrac{1}{f}=\dfrac{1}{f_1}+\dfrac{1}{f_2}=\dfrac{1}{5}-\dfrac{1}{25}=\dfrac{4}{25}

f=254f=\dfrac{25}{4}

Now, let the distance of object is u

1v1u=1f\Rightarrow \dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

1u=125425=325\Rightarrow \dfrac{1}{u}=\dfrac{1}{25}-\dfrac{4}{25}=\dfrac{3}{25}


So, u=253cmu=\dfrac{25}{3}cm

we know that,

hiho=vu\dfrac{h_i}{h_o}=\dfrac{-v}{u}

hi=25×3×225=6cmh_i=\dfrac{25\times 3\times 2}{25}=-6cm


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