As per the given question,
The power of the lenses are (P1)=+20D and (P2)=−4D
distance of distinct vision (v) =25cm
The size of the object (ho)=2cm
Let the focal length of the glasses are f1 and f2
We know that,
f1=P11=20100=5cm
Similarly,
f2=P21=4−100=−25cm
Now, combined focal length f1=f11+f21=51−251=254
f=425
Now, let the distance of object is u
⇒v1−u1=f1
⇒u1=251−254=253
So, u=325cm
we know that,
hohi=u−v
hi=2525×3×2=−6cm
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