As per the given question,
Power of the lens(P)=-1d
We know that "(f)=\\dfrac{1}{-d}=\\dfrac{-100}{d}cm"
As per the given question,
Let the height of the object "=(h_o)"
So, height of the the image "=\\dfrac{h_o}{2}"
We know that "m=\\dfrac{v}{u}=\\dfrac{h_1}{h_o}=0.5"
Hence, v= x and u = 2x
Now substituting the values,
"\\dfrac{1}{v}-\\dfrac{1}{u}=\\dfrac{1}{f}"
Now, substituting the values,
"\\dfrac{1}{x}+\\dfrac{1}{2x}=-\\dfrac{100}{d}"
Hence"\\dfrac{3}{2x}=-\\dfrac{100}{d}"
"x=-\\dfrac{200}{3}"
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