Question #108951

Sketch a ray diagram for a spherical convex lens with an object at Do = 2f.

Expert's answer

As per the given question,

Object position (u)=2f

Let the focal length of the spherical lens =f

let the final position of the image (v).

Now, we know that

1v1u=1f\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Now, substituting the values in the above,

1v12f=1f\Rightarrow \dfrac{1}{v}-\dfrac{1}{-2f}=\dfrac{1}{f}

1v=1f12f=12f\Rightarrow \dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{2f}=\dfrac{1}{2f}

Hence, v=2f


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