As per the given question,
Object position (u)=2f
Let the focal length of the spherical lens =f
let the final position of the image (v).
Now, we know that
"\\dfrac{1}{v}-\\dfrac{1}{u}=\\dfrac{1}{f}"
Now, substituting the values in the above,
"\\Rightarrow \\dfrac{1}{v}-\\dfrac{1}{-2f}=\\dfrac{1}{f}"
"\\Rightarrow \\dfrac{1}{v}=\\dfrac{1}{f}-\\dfrac{1}{2f}=\\dfrac{1}{2f}"
Hence, v=2f
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