The minimum distances
1a+1b=1f→1∞+1b=10.2→b=0.2m\frac{1}{a}+\frac{1}{b}=\frac{1}{f}\to\frac{1}{\infin}+\frac{1}{b}=\frac{1}{0.2}\to b=0.2ma1+b1=f1→∞1+b1=0.21→b=0.2m
The maximum distances
1a+1b=1f→12+1b=10.2→b=0.222m\frac{1}{a}+\frac{1}{b}=\frac{1}{f}\to\frac{1}{2}+\frac{1}{b}=\frac{1}{0.2}\to b=0.222ma1+b1=f1→21+b1=0.21→b=0.222m
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