Let's clarify the condition. So,
A glass wedge (μ=1.5 ) of angle 0.01 radian is illuminated by a monochromatic light of wave length 6330 A falling normally on it. At what distance from the edge of the wedge, will the 20 th fringe be observed by reflected light.
For bright bands
2μd=(2n+1)2λ
d=xn⋅tanα
2μ⋅xn⋅tanα=(2n+1)2λ
xn=4μα(2n+1)λ=4⋅1.5⋅0.01(2⋅20+1)⋅633⋅10−9≈0.00043m=0.43mm
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