R=mN=λ1λ2−λ1R=mN=\dfrac{\lambda_1}{\lambda_2-\lambda_1} R=mN=λ2−λ1λ1
λ1+λ22=600\frac{\lambda_1+\lambda_2}{2}=6002λ1+λ2=600 →λ1=1200−λ2\to\lambda_1=1200-\lambda_2→λ1=1200−λ2
m=1m=1m=1
So, we have
1200N−λ1N−λ1N=λ11200N-\lambda_1N-\lambda_1N=\lambda_11200N−λ1N−λ1N=λ1
1200N=λ1(2N+1)1200N=\lambda_1(2N+1)1200N=λ1(2N+1)
from these two equations we get
λ1=1200N2N+1=1200⋅20002⋅2000+1=599.85nm\lambda_1=\dfrac{1200N}{2N+1}=\dfrac{1200\cdot 2000}{2\cdot 2000+1}=599.85 nmλ1=2N+11200N=2⋅2000+11200⋅2000=599.85nm
λ2=1200−599.85=600.15nm\lambda_2=1200-599.85=600.15 nmλ2=1200−599.85=600.15nm
Hence the difference is
λ2−λ1=600.15−599.85=0.3nm\lambda_2-\lambda_1=600.15-599.85=0.3 nmλ2−λ1=600.15−599.85=0.3nm
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments