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1.One mole of oxygen at STP is adiabatically compressed to 5 atm. Calculate the final
temperature. Also, calculate the work done on the gas. Take g = 1.4 and
R = 8.31 J mol^-1 K^-1.
a) 1kg of water at 0oC(degree Celsius) is fully converted into steam at 100°C at normal pressure. Calculate the change in entropy. The specific heat capacity of water is
4.18X10^3 JKg^-1K^-1 and latent heat of vaporisation is 2.24x10^6 JKg^-1.
b) Calculate the work done by one mole of a van der Waals’ gas if during its isothermal
expansion its volume increases from 1m^3 to 2m^3 at a temperature 300K.
Take a = 1.39X10^-6 atm m^6 mol^-2 and b = 39.1X10^-6 m^3 mol^-1.
if we boil a load of aluminum beads in water until everything reaches the same temperature. We then use a wire mesh strainer to quickly transfer the balls to a calorimeter containing .2 kg of water at 20 degrees celsius. The final temperature is 60 degrees celsius. This is so the temperature drop of the aluminum exactly equals the temperature gain of the water. The mass of the aluminum beads is .944 kg. What is the specific heat of aluminum? c of water=4186 J/kg
a gardener wishes the water from his hose was able to reach flowers 3m away when he holds the nozzle horizontally at a height of 1m. He finds out that the water has a speed of 6.64 m/s when it leaves his hose. The nozzle of his hose has an inner diameter of 1.5 cm. The other end is connected to a pipe with an inner diameter of 2 cm. What must the pressure in the exit pipe be for the water from his hose to reach his flowers?
An ideal calorimeter has 2.5 kg of water at room temp. We put 1.25 kg of aluminum beads that are at a temp of 115 degrees Celsius. We add in .3 kg of ice at -10 degrees Celsius. What final temp. Do the materials in the calorimeter come to?
The surface of a ball of radius A is kept at a temperature zero. If the initial temperature in the
ball is f (r), write down the boundary conditions and show that the temperature in the ball at
time t, u (r, t), is the solution to the equation:
c^2[(d^2u/dr^2)+2/r(du/dr)]=du/dt
note: here every du/dr or du/dt stands for partial differentiation wrt respected term
Prepare a cell containing copper sulphate solution and two copper plates. Determine its internal resistance with the help of a potentiometer. New repeat the experiment by changing the concentration of the solution. For this remove about 50 ml CuSo4 solution and add similar amount of water in the cell. For the purpose of measurement you can use a doctor’s syringe. Do you find any change in the internal resistance of the cell? Also change the (i) plate area immersed in the electrolyte and (ii) separation between the plates. Write various factors on which internal resistance of a cell depends.
the volume of a gas is reduced by compressing it under adiabatic conditions.if the work done on the gas is 200J,find the change in internal energy of the gas and also the amount of heat absorbed by the gas.
A force of 315 N is applied horizontally to a crate in order to displace the crate 37.5 m across a level floor at a constant velocity. As a result of this work, the crate's internal energy is increased by an amount equal to 21 percent of the crate's initial internal energy. Calculate the initial internal energy of the crate.
The highest recorded temperature on Krypton was 142 degrees F. The lowest recorded tempera- ture was −93 degrees F. Express the low temperature extreme in degrees Celsius. Answer in units of degrees C.
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