1)
"U=2.5nRT_1\\to T_1=\\frac{2E}{5nR}" 2)
"U=(1-\\alpha)2.5nRT_2+(\\alpha)1.5(2n)RT_2\\to T_1=\\frac{2E}{(5+\\alpha)nR}" 3) The fractional change in its temperature is:
"\\frac{\\frac{2E}{(5+\\alpha)nR}-\\frac{2E}{5nR}}{\\frac{2E}{5nR}}=\\frac{-\\alpha}{5+\\alpha}"
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