Question #99877
The change of internal energy of an ideal gas is 300 J. What is the total heat added into the gas if it expands for 2.010−3 m3 under 1.01105 Pa
1
Expert's answer
2019-12-05T10:23:05-0500

1st law of thermodynamics give it


Q=ΔU+pΔVQ=\Delta U+p\Delta V

Initial conditions


ΔU=300;p=1.01105(Pa);ΔV=2.0103(m3)\Delta U=300; p=1.01 \cdot 10^5 (Pa); \Delta V=2.0\cdot 10^{-3} (m^3)

Calculating


Q=300+1.011052.0103=502(J)Q=300+1.01\cdot 10^5 \cdot 2.0\cdot 10^{-3}=502 (J)


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