Answer to Question #99030 in Molecular Physics | Thermodynamics for Rupika Sood

Question

A force of 30 N is applied to a body of mass 5.0 kg which is moving at speed 4.0 m/s. The final speed of the body after 2.0 a is [16] m/s

Answer 1

Solution:

$$F=m\times a$$

$$a=\frac{F}{m}$$

$$a=\frac{30 N}{5 kg}=6\frac{m}{s^2}$$

$$v=v_0+a\times t$$

$$t=\frac {v-v_0}{a}=\frac{16-4}{6}= 2 s$$

Answer: 2s