Question

Calculate the energy required in joules to raise the temperature of 450 grams of water from 15°C to 85°C. (The specific heat capacity of water is 4.18 J/g/°C)

Answer 1

The requaierd energy can be caclulated as

$$Q = cm\Delta T$$

Where $c$ - the specific heat capacity of water, $m$ - mass of water, $\Delta T$ - temperature defference. We get

$$Q = 4.18[{{\rm{J}} \over {{\rm{g}} \cdot {\rm{^\circ C}}}}] \cdot 450[{\rm{g}}] \cdot (85[{\rm{^\circ C}}] - 15[{\rm{^\circ C}}]) = 131670[{\rm{J}}]$$