Question #94780

If it takes 10minutes for the temperature of initial to fall from 100°c to 80°c within a surround temperature of 30°c. Calculate the Temperature of the initial after 30minutes


1
Expert's answer
2019-09-19T09:47:36-0400

We have:


TTa=Aexp(kt)T-T_a=A\exp{(-kt)}

The initial conditions:


10030=AA=70°C100-30=A\to A=70\degree C

Now,

8030=70exp(k(10))80-30=70\exp{(-k(10))}

k=0.1ln1.4k=0.1\ln{1.4}

So, temperature of the initial after 30 minutes:

T=30+70exp(0.1ln1.4(30))=55.5°CT=30+70\exp{(-0.1\ln{1.4}(30))}=55.5\degree C



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