Question

Find the value of absolute zero on the Fahrenheit scale

Answer 1

Absolute zero is 0 K.

$T [K] = 273 + 5/9 \cdot (T [\degree F] - 32)$

$T [\degree F] = 9/5 \cdot (T [K] - 273) + 32$

$T [\degree F] = 9/5 \cdot (0 - 273) + 32 = -459.4 \; \degree F$

Answer: $-459.4 \; \degree F$.