Question #90487
An impulse of 10 kilogram-meter per second acting on an object whose mass is 5 kilogram will cause a change in the objects velocity of: find the solution
1
Expert's answer
2019-06-03T10:39:38-0400

Impulse acting on an object is the change in momentum of an object


Δp=Δ(mv)\Delta p=\Delta \left( mv \right)

Since the mass m does not change, then impulse of object is

Δp=mΔv\Delta p=m\Delta v

Dividing both sides of the equation by m, we get the change in velocity


Δv=Δpm\Delta v=\frac{\Delta p}{m}

Substituting Δp=10 kg-meter per second\Delta p=10\text{ }kg\text{-}meter\text{ }per\text{ }second and m=5 kgm=5\text{ }kg we get change in the objects velocity


Δv=10kg-meter per second5kg=2meter per second\Delta v=\frac{10\,\,kg\text{-}meter\text{ }per\text{ }second}{5\,kg}=2\,meter\text{ }per\text{ }second


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