Question #89309

Starting with the equation of motion, prove that the phase space of a linear harmonic oscillator is elliptical.

Expert's answer

The equation of motion of a harmonic oscillator has the following form:


x¨+ω02x=0\ddot{x} + \omega_0^2 x = 0

By introducing the new variable


y=x˙y = \dot{x}

we transform the initial 2nd order ODE into the set of the two 1st order ODEs:


y˙=−ω02xx˙=y\dot{y} = - \omega_0^2 x \\ \dot{x} = y

Excluding time, we come to the single ODE defining the phase portrait of the system:


dydx=−ω02xy\frac{dy}{dx} = - \frac{\omega_0^2 x}{y}

Performing the integration, we obtain:


y22+ω02x22=c2\frac{y^2}{2} + \frac{\omega_0^2 x^2}{2} = c^2

Introducing the notations


a2≡2c2ω02,b2≡2c2,a^2 \equiv \frac{2 c^2}{\omega_0^2}, \quad b^2 \equiv 2 c^2,

we obtain


x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1

which is the canonical equation of an ellipse.



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