Question #88749
Starting from the equation of motion of a
linear harmonic oscillator, show that its
phase space is an ellipse.
1
Expert's answer
2019-05-03T09:25:43-0400

The equation of motion of a linear harmonic oscillator


x¨(t)+ω2x(t)=0\ddot{x}(t)+\omega^2x(t)=0

Solution of this equation defines the position of the oscillator with time

x(t)=Asin(ωt+ϕ)x(t)=A\sin(\omega t+\phi)

The linear momentum of a linear harmonic oscillator

p(t)=mx˙(t)=mωAcos(ωt+ϕ)p(t)=m\dot{x}(t)=m\omega A\cos(\omega t+\phi)

Using two last equations we obtain the phase trajectory equation

p2(mωA)2+x2A2=1\frac{p^2}{(m\omega A)^2}+\frac{x^2}{A^2}=1

Therefore the phase space of a linear harmonic oscillator is an ellipse with semi-axes

a=mωA,b=Aa=m\omega A, \quad b=A


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