Question #88528
Determine the temperature, volume, internal energy, enthalpy, entropy and density of 2kg of
steam at a pressure of 2MM/m2 and with a dryness fraction of 0.85.
1
Expert's answer
2019-04-25T09:31:04-0400

For this problem we need h,S diagram


On this diagram find a point where across two lines: pressure 20 bar and dryness fraction 0,85

For it we have

Entropy per kg

S=5.7565(kJkgK)S=5.7565 (\frac{kJ}{kg\cdot K})

Enthalpy per kg

i=2516(kJkg)i=2516 (\frac{kJ}{kg})


Volume per kg


Vm=0.0878(m3kg)\frac{V}{m}=0.0878 (\frac{m^3}{kg})


Find internal energy from this equation

i=U+pVi=U+pV

Internal energy

U=ipVU=i-pV

For temperature use this equation

T=didST=\frac{di}{dS}T=255025165.75655.826273=216CT=\frac{2550-2516}{5.7565-5.826}-273=216 ^\circ C

Density

ρ=mV=11.4(kgm3)\rho=\frac{m}{V}=11.4 (\frac{kg}{m^3})

So, for 2 kg mass of steam and pressure 20 bar, we have

Volume

V=0.08782=0.1756(m3)V=0.0878*2=0.1756 (m^3)

Internal energy

U=503221030.1756=4681(kJ)U=5032-2\cdot 10^{3} \cdot 0.1756=4681 (kJ)

Enthalpy

i=25162=5032(kJ)i=2516*2=5032 (kJ)

Entropy

S=5.75652=11.513(kJK)S=5.7565*2=11.513 (\frac{kJ}{K})


Density

ρ=11.4(kgm3)\rho=11.4 (\frac{kg}{m^3})

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS