For this problem we need h,S diagram
On this diagram find a point where across two lines: pressure 20 bar and dryness fraction 0,85
For it we have
Entropy per kg
S=5.7565(kg⋅KkJ)Enthalpy per kg
i=2516(kgkJ)
Volume per kg
mV=0.0878(kgm3)
Find internal energy from this equation
i=U+pV Internal energy
U=i−pVFor temperature use this equation
T=dSdiT=5.7565−5.8262550−2516−273=216∘CDensity
ρ=Vm=11.4(m3kg)So, for 2 kg mass of steam and pressure 20 bar, we have
Volume
V=0.0878∗2=0.1756(m3) Internal energy
U=5032−2⋅103⋅0.1756=4681(kJ)Enthalpy
i=2516∗2=5032(kJ)Entropy
S=5.7565∗2=11.513(KkJ)
Density
ρ=11.4(m3kg)
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