For this problem we need h,S diagram
On this diagram find a point where across two lines: pressure 20 bar and dryness fraction 0,85
For it we have
Entropy per kg
"S=5.7565 (\\frac{kJ}{kg\\cdot K})"Enthalpy per kg
"i=2516 (\\frac{kJ}{kg})"Volume per kg
Find internal energy from this equation
"i=U+pV"Internal energy
"U=i-pV"For temperature use this equation
"T=\\frac{di}{dS}""T=\\frac{2550-2516}{5.7565-5.826}-273=216 ^\\circ C"Density
"\\rho=\\frac{m}{V}=11.4 (\\frac{kg}{m^3})"So, for 2 kg mass of steam and pressure 20 bar, we have
Volume
"V=0.0878*2=0.1756 (m^3)"Internal energy
"U=5032-2\\cdot 10^{3} \\cdot 0.1756=4681 (kJ)"Enthalpy
"i=2516*2=5032 (kJ)"Entropy
"S=5.7565*2=11.513 (\\frac{kJ}{K})"Density
"\\rho=11.4 (\\frac{kg}{m^3})"
Comments
Leave a comment