To find the size of the smallest feature observable in human tissue using ultrasound we calculate the ultrasound wavelength λ using the formula
λ=fcwhere c is the speed of sound in human tissue, f is the frequency of sound. We are given
c=1,540 m/s=1.54⋅103m/s,f=15MHz=1.5⋅107Hz
Substituting these values in the formula, we get
λ=fc=1.5⋅107Hz1.54⋅103m/s≈1.03⋅10−4m
Since one meter equals 100 centimeters we get
λ≈1.03⋅10−4m⋅100cm/m=1.03⋅10−2cm
We can also write the wavelength in millimeters
λ≈1.03⋅10−2cm⋅10mm/cm=1.03⋅10−1mm=0.103mm
So the size of the smallest feature observable in human tissue when examined with 15-MHz ultrasound is 0.103 mm
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