Answer to Question #88015 in Molecular Physics | Thermodynamics for gc

Question #88015
A boat (with a flat bottom) and its cargo weigh 7,400 N. The area of the boat's bottom is 3 m2. How far below the surface of the water is the boat's bottom when it is floating in water?
1
Expert's answer
2019-04-15T10:17:36-0400

Archimedes' principle - weight of displaces fluid equals to weight of object.

Density of water ρ=1000kg m3\rho = 1000\, \text{kg m}^{-3}

Gravity acceleration g=9.8ms2g= 9.8\, \text{ms}^{-2}


F=7400N=mg=ρShgF = 7400\, \text{N} = m\cdot g = \rho S h g


h=FρSg=7400100039.8m=25cmh= \frac{F}{\rho S g} = \frac{7400}{1000\cdot 3 \cdot 9.8}\, \text{m} = 25\, \text{cm}

Answer: 25 centimeter


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment